Question

in a two - point cross to map genes a and b, you obtained 98 recombinant types and 902 parental types among the offspring. how far apart are these genes? multiple choice 9.8 cm 9.02 cm 0.98 cm 90.2 cm 0.98 cm

Explanation:

Step1: Calculate total offspring

Total = recombinant + parental = 98 + 902 = 1000

Step2: Compute recombination frequency

Recombination frequency = $\frac{\text{Recombinant}}{\text{Total}} \times 100$ = $\frac{98}{1000} \times 100$ = 9.8%

Step3: Convert to cM

1% recombination = 1 cM, so 9.8% = 9.8 cM

Answer:

9.8 cM