Question

1. two parents think their baby was switched at the hospital. its 1968, so dna fingerprinting technology does not exist yet. the mother has blood type \o,\ the father has blood type \ab,\ and the baby has blood type \o.\

a. mothers genotype:

b. fathers genotype:

c. babys genotype:

d. draw a punnett square showing
all possible genotypes for children.
e. was the baby switched?

Explanation:

Step1: Determine Mother's Genotype

Blood type O is recessive, so the genotype must be \( ii \) (or \( OO \) in some notations). The mother has blood type O, so her genotype is \( ii \).

Step2: Determine Father's Genotype

Blood type AB has the genotype \( I^A I^B \), as AB blood type is co - dominant, with both A and B alleles present. The father has blood type AB, so his genotype is \( I^A I^B \).

Step3: Determine Baby's Genotype

Blood type O is recessive, so the baby's genotype must be \( ii \) (since to have O blood type, the baby must inherit an \( i \) allele from both parents).

Step4: Draw Punnett Square

The mother can only pass on \( i \) alleles. The father can pass on \( I^A \) or \( I^B \) alleles.

	\( I^A \)	\( I^B \)
\( i \)	\( I^A i \)	\( I^B i \)

So the possible genotypes for children are \( I^A i \) (blood type A) and \( I^B i \) (blood type B). There is no possible way for the child to have genotype \( ii \) (blood type O) from these parents.

Step5: Determine if Baby was Switched

Since the possible blood types of children from a mother with genotype \( ii \) and a father with genotype \( I^A I^B \) are A and B (genotypes \( I^A i \) and \( I^B i \)), and the baby has blood type O (genotype \( ii \)), the baby was switched.

Answer:

s:
a. Mother's genotype: \(\boldsymbol{ii}\) (or \(\boldsymbol{OO}\))
b. Father's genotype: \(\boldsymbol{I^A I^B}\) (or \(\boldsymbol{AB}\))
c. Baby's genotype: \(\boldsymbol{ii}\) (or \(\boldsymbol{OO}\))
d. Punnett Square (as above):

	\( I^A \)	\( I^B \)
\( i \)	\( I^A i \)	\( I^B i \)

e. Was the baby switched? \(\boldsymbol{Yes}\)