Question

two cats are both heterozygous for hair length, ss, and heterozygous for white hair, ww. short hair and white hair are dominant to long hair and colored hair, respectively. what are the odds that the pairs offspring would show the following phenotypes (proportions can be used more than once)? drag each item on the left to its matching item on the right. note that every item may not have a match, while some items may have more than one match. long, colored hair long, white hair 1/16 3/16 9/16 short, colored hair short, white hair

Explanation:

Step1: Determine gametes

Each cat (SsWw) can produce 4 types of gametes: SW, Sw, sW, sw.

Step2: Set up Punnett - square

A di - hybrid cross (4x4 Punnett - square) will have 16 possible combinations of gametes.

Step3: Calculate phenotypes

• Long, colored hair (ssww): There is 1 out of 16 combinations, so the proportion is $\frac{1}{16}$.
• Long, white hair (ssW -): There are 3 out of 16 combinations (ssWW, ssWw, ssWw), so the proportion is $\frac{3}{16}$.
• Short, colored hair (S - ww): There are 3 out of 16 combinations (SSww, Ssww, Ssww), so the proportion is $\frac{3}{16}$.
• Short, white hair (S - W -): There are 9 out of 16 combinations (SSWW, SSWw, SsWW, SsWw, SSWw, SsWW, SsWw, SsWw, SsWw), so the proportion is $\frac{9}{16}$.

Answer:

Long, colored hair: $\frac{1}{16}$
Long, white hair: $\frac{3}{16}$
Short, colored hair: $\frac{3}{16}$
Short, white hair: $\frac{9}{16}$