Question

two buses are leaving from different schools to carry students to a band competition. bus a travels 160 miles the first day, and an average of 60 miles per hour on the second day. bus b travels 240 miles the first day of the trip, and an average of 50 miles per hour on the second day. after how many hours on the second day will both buses have driven the same total number of miles?
let h represent the number of hours. select the correct values to write an equation to represent the situation.
bus a: select choice + select choice h = bus b: select choice + select choice h
part b
solve the equation. after how many hours on the second day will both buses have driven the same total number of miles?
____ hours

Explanation:

Step1: Define total miles for each bus

Bus A: First day miles = 160, second day rate = 60 mph. So total miles: \( 160 + 60h \).
Bus B: First day miles = 240, second day rate = 50 mph. So total miles: \( 240 + 50h \).

Step2: Set equations equal (same total miles)

\( 160 + 60h = 240 + 50h \)

Step3: Solve for \( h \)

Subtract \( 50h \) and 160 from both sides:
\( 60h - 50h = 240 - 160 \)
\( 10h = 80 \)

Step4: Divide to find \( h \)

\( h = \frac{80}{10} = 8 \)

Answer:

The equation is \( 160 + 60h = 240 + 50h \), and \( h = 8 \) hours.