Question

two bowling balls of different masses collide while accelerating at 1.875 m/s². the first ball, rolling to the right, weighs 7 kg. the second ball, rolling to the left, weighs 4 kg. what force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg? (1 point) 13.125 n to the right 7.5 n to the left 8.875 n to the right 3.73 n to the right

Explanation:

Step1: Use Newton's second law

Newton's second law is \(F = ma\). Here, \(m = 7\space kg\) and \(a=1.875\space m/s^{2}\).

Step2: Calculate the force

Substitute the values into the formula: \(F=(7\space kg)\times(1.875\space m/s^{2}) = 13.125\space N\). The direction of the force is the same as the direction of acceleration of the \(7 - kg\) ball (to the right).

Answer:

13.125 N to the right