two angles of a triangle are given below. ?°, 100°, 40° find the measure of the 3rd angle.

Question

Accepted Answer

# Explanation:
## Step1: Recall the sum of angles in a triangle
The sum of the interior angles of a triangle is $180^{\circ}$. Let the unknown angle be $x$. Then $x + 100^{\circ}+40^{\circ}=180^{\circ}$.
## Step2: Solve for $x$
$$
\begin{align*}
x&=180^{\circ}-(100^{\circ} + 40^{\circ})\
x&=180^{\circ}-140^{\circ}\
x& = 40^{\circ}
\end{align*}
$$

# Answer:
$40^{\circ}$

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Question

Explanation:

Step1: Recall the sum of angles in a triangle

Step2: Solve for \(x\)

Answer: