Question

your turn! a photon has a wavelength of 462×10⁻⁹ m. calculate the energy of the photon in joules. e = \frac{hc}{\lambda}, c is the speed of light 3.00×10⁸m/s, h is plancks constant 6.626×10⁻³⁴ js, \lambda is wavelength (must be in meters)

Explanation:

Step1: Identify given values

$h = 6.626\times 10^{-34}\ J\cdot s$, $c = 3.00\times 10^{8}\ m/s$, $\lambda=462\times 10^{-9}\ m$

Step2: Substitute values into formula

$E=\frac{hc}{\lambda}=\frac{6.626\times 10^{-34}\times3.00\times 10^{8}}{462\times 10^{-9}}$

Step3: Calculate the result

$E=\frac{19.878\times 10^{-26}}{462\times 10^{-9}}=\frac{1.9878\times 10^{-25}}{4.62\times 10^{-7}} \approx 4.3\times 10^{-19}\ J$

Answer:

$4.3\times 10^{-19}\ J$