Question

try again your answer is incorrect. given $f(x)=x^3 - 2$, find the equation of the secant line passing through $(-4, f(-4))$ and $(2, f(2))$. write your answer in the form $y = mx + b$.

Explanation:

Step1: Calculate f(-4) and f(2)

$f(-4)=(-4)^3 -2=-64-2=-66$; $f(2)=2^3 -2=8-2=6$

Step2: Compute slope m

$m=\frac{f(2)-f(-4)}{2-(-4)}=\frac{6-(-66)}{6}=\frac{72}{6}=12$

Step3: Find intercept b

Use point (2,6): $6=12×2 + b → b=6-24=-18$

Answer:

$y=12x-18$