Question

a truck initially at rest accelerates uniformly to 43.0 m/s over 8.50 s. what is the acceleration of the truck?

a = ? m/s²

Explanation:

Step1: Recall the acceleration formula

Acceleration \( a \) is defined as the change in velocity \( \Delta v \) over the change in time \( \Delta t \), so \( a=\frac{\Delta v}{\Delta t} \). The initial velocity \( v_0 = 0\) (at rest), final velocity \( v = 43.0\space m/s \), time \( t = 8.50\space s \). So \( \Delta v=v - v_0=43.0 - 0 = 43.0\space m/s \), \( \Delta t = 8.50\space s \).

Step2: Calculate acceleration

Substitute into the formula: \( a=\frac{43.0}{8.50}\space m/s^2 \). Calculate the value: \( \frac{43.0}{8.50}\approx5.06\space m/s^2 \) (rounded to two decimal places).

Answer:

\( 5.06 \) (or more precisely \( \frac{43}{8.5}\approx5.0588\approx5.06 \))