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Question
6.4 trinomials where a does n
(1 point)
factor:
$8x^2 + 14x + 5 = \square$
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Step1: Find product of leading coefficient and constant
$8 \times 5 = 40$
Step2: Find two numbers multiplying to 40 and adding to 14
Numbers: 4 and 10 (since $4 \times 10 = 40$, $4 + 10 = 14$)
Step3: Split middle term using these numbers
$8x^2 + 4x + 10x + 5$
Step4: Factor by grouping
$4x(2x + 1) + 5(2x + 1) = (4x + 5)(2x + 1)$
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$(4x + 5)(2x + 1)$