Question

6.4 trinomials where a does not equ
(1 point)
factor:
$4x^3 + 12x^2 - 40x = \square$
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Explanation:

Step1: Factor out the greatest common factor (GCF)

The GCF of \(4x^{3}\), \(12x^{2}\), and \(-40x\) is \(4x\).

$$4x^{3}+12x^{2}-40x = 4x(x^{2}+3x - 10)$$

Step2: Factor the quadratic expression \(x^{2}+3x - 10\)

We need to find two numbers that multiply to \(-10\) and add up to \(3\). The numbers are \(5\) and \(-2\).

$$x^{2}+3x - 10=(x + 5)(x-2)$$

Answer:

\(4x(x + 5)(x - 2)\)