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Question
in triangle rst, m∠r > m∠s + m∠t. which must be true of triangle rst? check all that apply. m∠r > 90° m∠s + m∠t < 90° m∠s = m∠t m∠r > m∠t m∠r > m∠s m∠s > m∠t
Step1: Recall angle - sum property of a triangle
The sum of the interior angles of a triangle is \(m\angle R + m\angle S+m\angle T = 180^{\circ}\), so \(m\angle S + m\angle T=180^{\circ}-m\angle R\).
Step2: Use the given inequality
Given \(m\angle R>m\angle S + m\angle T\). Substitute \(m\angle S + m\angle T = 180^{\circ}-m\angle R\) into the inequality: \(m\angle R>180^{\circ}-m\angle R\).
Step3: Solve the inequality for \(m\angle R\)
Add \(m\angle R\) to both sides: \(m\angle R+m\angle R>180^{\circ}\), \(2m\angle R>180^{\circ}\), then \(m\angle R > 90^{\circ}\).
Step4: Analyze other inequalities
Since \(m\angle R>m\angle S + m\angle T\), it is clear that \(m\angle R>m\angle T\) and \(m\angle R>m\angle S\) because \(m\angle S\geq0^{\circ}\) and \(m\angle T\geq0^{\circ}\). Also, since \(m\angle R>90^{\circ}\) and \(m\angle R + m\angle S+m\angle T = 180^{\circ}\), then \(m\angle S + m\angle T=180^{\circ}-m\angle R<90^{\circ}\).
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