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triangle proofs quick check use the image to answer the question consid…

Question

triangle proofs quick check
use the image to answer the question
consider the following proof of the base angles theorem. which statement should fill in the blank?
proof given isosceles △abc with \\( \overline { a b } \cong \overline { b c } \\). i can construct \\( \overleftrightarrow { b d } \\) the angle bisector of \\( \angle b \\) ____________. i also know that line segments are congruent to themselves, so \\( \overline { b d } \cong \overline { b d } \\) by the reflexive property of congruence. i now have two pairs of sides and an included angle that are congruent, so i know that \\( \triangle a b d \cong \triangle c b d \\) by the sas congruence theorem. finally, corresponding parts of congruent triangles are congruent by the cpctc theorem, so \\( \angle a \cong \angle c \\).
(1 point)
then, by the definition of an angle bisector, i know that \\( \angle b a c \cong \angle b c a \\)
then, by the definition of an angle bisector, i know that \\( \angle a b d \cong \angle c b d \\)
then, by the definition of a midpoint, i know that \\( \overline { a d } \cong \overline { d c } \\)
then, by the definition of an isosceles triangle, i know that \\( \overline { a b } \cong \overline { c a } \\)

Explanation:

Step1: Analyze the role of angle bisector

An angle bisector divides an angle into two congruent angles. Here, \( \overrightarrow{BD} \) is the angle bisector of \( \angle B\).

Step2: Apply the definition of angle bisector

By the definition of an angle bisector, if \( \overrightarrow{BD} \) bisects \( \angle B\) in \( \triangle ABC\), then \( \angle ABD\) and \( \angle CBD\) are the two angles formed by the bisector. So, \( \angle ABD\cong\angle CBD\)

Option A is wrong because \( \angle BAC\) and \( \angle BCA\) are not related to the angle - bisector \( \overrightarrow{BD}\) in terms of the angle - bisector definition. Option C is wrong because there is no information given about \( D\) being a mid - point (a mid - point would make \( \overline{AD}\cong\overline{DC}\), but we are dealing with an angle bisector here). Option D is wrong because \( \overline{AB}\cong\overline{BC}\) is given (the triangle is isosceles with \( \overline{AB}\cong\overline{BC}\)), not \( \overline{AB}\cong\overline{CA}\)

Answer:

B. Then, by the definition of an angle bisector, I know that \( \angle ABD\cong\angle CBD \)