Question

triangle jkl has coordinates j(-8,5), k(-4,4), and l(-3,1). what are the coordinates of the image after a reflection in the y - axis?
a) j(8,5), k(4,4), l(3,1)
b) j(-8,-5), k(-4,-4), l(-3,-1)
c) j(-5,-8), k(-4,-4), l(-1,-3)
d) j(5,8), k(4,4), l(1,3)

Explanation:

Step1: Recall reflection over y - axis rule

The rule for reflecting a point \((x,y)\) over the \(y\) - axis is \((x,y)\to(-x,y)\).

Step2: Apply the rule to point \(J(-8,5)\)

For point \(J(-8,5)\), using the reflection rule \((x,y)\to(-x,y)\), we substitute \(x = - 8\) and \(y = 5\). So \(J'=( - (-8),5)=(8,5)\).

Step3: Apply the rule to point \(K(-4,4)\)

For point \(K(-4,4)\), using the reflection rule \((x,y)\to(-x,y)\), we substitute \(x=-4\) and \(y = 4\). So \(K'=( - (-4),4)=(4,4)\).

Step4: Apply the rule to point \(L(-3,1)\)

For point \(L(-3,1)\), using the reflection rule \((x,y)\to(-x,y)\), we substitute \(x = - 3\) and \(y=1\). So \(L'=( - (-3),1)=(3,1)\).

Answer:

A) \(J'(8,5),K'(4,4),L'(3,1)\)