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Question
triangle def is translated 9 units to the right and 6 units up. the result is △def, as shown below. (a) the arrows below show that the coordinates on the left are mapped to the coordinates on the right. fill in the blanks to give the coordinates after the translation. original coordinates → final coordinates d(-7, -4) → d(□,□) e(-8, -1) → e(□,□) f(-4, -5) → f(□,□) (b) choose the general rule below that describes the translation mapping △def to △def. (x, y) → (x + 9, y + 6) (x, y) → (x + 6, y + 9) (x, y) → (x - 6, y - 9) (x, y) → (-9x, -6y) (x, y) → (-6x, -9y) (x, y) → (9x, 6y) (x, y) → (6x, 9y) (x, y) → (x - 9, y - 6)
Step1: Calculate \(D'\) coordinates
For a translation \(9\) units right (add \(9\) to \(x\) - coordinate) and \(6\) units up (add \(6\) to \(y\) - coordinate).
For \(D(-7,-4)\), \(x=-7 + 9=2\), \(y=-4 + 6 = 2\).
Step2: Calculate \(E'\) coordinates
For \(E(-8,-1)\), \(x=-8 + 9 = 1\), \(y=-1+6 = 5\).
Step3: Calculate \(F'\) coordinates
For \(F(-4,-5)\), \(x=-4 + 9=5\), \(y=-5 + 6 = 1\).
Step4: Determine the general rule
The translation rule for \(x\) - coordinate is \(x\to x + 9\) (right \(9\) units) and for \(y\) - coordinate is \(y\to y + 6\) (up \(6\) units). So the rule is \((x,y)\to(x + 9,y + 6)\).
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(a) \(D'=(2,2)\), \(E'=(1,5)\), \(F'=(5,1)\)
(b) \((x,y)\to(x + 9,y + 6)\)