Question

triangle cde with vertices c(2,-1), d(7,-4), and e(4,-6): (x,y)→(x - 3,y + 8) c (__,) d (,) e (,__)

Explanation:

Step1: Find \(C'\)

For point \(C(2,-1)\), use the transformation \((x,y)\to(x - 3,y + 8)\).
\(x\) - coordinate: \(2-3=-1\), \(y\) - coordinate: \(-1 + 8=7\). So \(C'(-1,7)\).

Step2: Find \(D'\)

For point \(D(7,-4)\), use the transformation \((x,y)\to(x - 3,y + 8)\).
\(x\) - coordinate: \(7-3 = 4\), \(y\) - coordinate: \(-4+8 = 4\). So \(D'(4,4)\).

Step3: Find \(E'\)

For point \(E(4,-6)\), use the transformation \((x,y)\to(x - 3,y + 8)\).
\(x\) - coordinate: \(4-3=1\), \(y\) - coordinate: \(-6 + 8=2\). So \(E'(1,2)\).

Answer:

\(C'(-1,7)\), \(D'(4,4)\), \(E'(1,2)\)