Question

if a translation of $t_{-3, -8}(x,y)$ is applied to square abcd, what is the $y$-coordinate of $b$?
-12
-8
-6
-2

Explanation:

Step1: Determine the original y - coordinate of point B

From the graph, the coordinates of point B are \((1,2)\). So the original \(y\) - coordinate of \(B\) is \(y = 2\).

Step2: Apply the translation rule for the y - coordinate

The translation rule \(T_{-3,-8}(x,y)=(x - 3,y-8)\). For the \(y\) - coordinate, we use the formula \(y'=y - 8\). Substitute \(y = 2\) into the formula: \(y'=2-8\).

$$y'=2-8=-6$$

Answer:

\(-6\)