Question

translate triangle abc by 5 units to the right and 4 units up. which of the following are the coordinates of the new triangle abc (1 point) o a(9,9),b(7,5),c(12,7) o a(-1,9),b(7,3),c(2,7) o a(-1,9),b(-3,5),c(2,7) o a(9,7),b(7,3),c(2,7)

Explanation:

Step1: Identify original coordinates

From the graph, \(A(3,5)\), \(B(2,1)\), \(C(6,3)\)

Step2: Apply translation rule

The translation rule for moving 5 units to the right and 4 units up is \((x,y)\to(x + 5,y+4)\)
For point \(A\): \(x=3,y = 5\), new \(x=3 + 5=8\), new \(y=5 + 4=9\), so \(A'(8,9)\)
For point \(B\): \(x = 2,y=1\), new \(x=2+5 = 7\), new \(y=1 + 4=5\), so \(B'(7,5)\)
For point \(C\): \(x=6,y = 3\), new \(x=6+5=11\), new \(y=3 + 4=7\), so \(C'(11,7)\)
However, there seems to be a mistake in the options provided. If we assume some calculation - based errors in the options and re - calculate:
For a point \((x,y)\) translated 5 units right and 4 units up.
Let's re - check the general rule application.
For \(A(3,5)\): \(A'(3 + 5,5+4)=(8,9)\)
For \(B(2,1)\): \(B'(2 + 5,1+4)=(7,5)\)
For \(C(6,3)\): \(C'(6 + 5,3+4)=(11,7)\)
If we assume there are typos in the options and we consider the closest correct - looking option based on the rule \((x,y)\to(x + 5,y + 4)\)

Answer:

None of the given options are correct. But if we assume some mis - printing in options and go by the closest values following the translation rule, the closest would be \(A'(8,9),B'(7,5),C'(11,7)\) (not among the provided options)