a total of 5500 lbs of mlss are desired in the aeration tank. what is the desired mlss concentration, in mg/l, if the aeration tank volume is 250,000 gallons?

28.36 mg/l
2.386 mg/l
268.3 mg/l
2638 mg/l

Question

a total of 5500 lbs of mlss are desired in the aeration tank. what is the desired mlss concentration, in mg/l, if the aeration tank volume is 250,000 gallons?

28.36 mg/l
2.386 mg/l
268.3 mg/l
2638 mg/l

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "MLSS Mass Calculation" ], "new_concepts": [], "current_concepts": [ "MLSS Mass Calculation", "Wastewater Calculations" ] } ## Identify given values and formula $$ \begin{aligned} &\text{Mass of MLSS} = 5500\text{ lbs} \ &\text{Volume of tank } (V) = 250,000\text{ gallons} = 0.25\text{ MGD} \ &\text{Formula: } \text{Mass (lbs)} = \text{Concentration (mg/L)} \times \text{Volume (MG)} \times 8.34\text{ lbs/gal} \end{aligned} $$ ## Solve for concentration $$ \begin{aligned} &\text{Concentration (mg/L)} = \frac{\text{Mass (lbs)}}{\text{Volume (MG)} \times 8.34} \ &\text{Concentration (mg/L)} = \frac{5500}{0.25 \times 8.34} \end{aligned} $$ ## Calculate final numerical value $$ \begin{aligned} &\text{Concentration (mg/L)} = \frac{5500}{2.085} \approx 2637.89\text{ mg/L} \approx 2638\text{ mg/L} \end{aligned} $$

(A) 28.36 mg/L

(B) 2.386 mg/L

(C) 268.3 mg/L

(D) 2638 mg/L

{ "subject": "Natural Science", "question_type": "Multiple Choice", "knowledge_point": [ "Natural Science", "Environmental Science", "Wastewater Treatment Calculations" ] }

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Question

Explanation:

Identify given values and formula

Solve for concentration

Calculate final numerical value

Answer: