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Question
topic: writing the equation of a line
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write the equation of the line with a slope of 4 that contains the point (5,8).
y = 4x - 27
y = 4x + 28
y = 4x + 8
y = 4x - 12
Step1: Use point-slope form
Point-slope form: $y - y_1 = m(x - x_1)$, where $m=4$, $(x_1,y_1)=(5,8)$
Substitute: $y - 8 = 4(x - 5)$
Step2: Simplify to slope-intercept form
Expand right side: $y - 8 = 4x - 20$
Add 8 to both sides: $y = 4x - 12$
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D. $y = 4x - 12$