Question

if it took a boy 45 seconds to push a 20 - kg wagon 5 meters with a force of 9 newtons, what was the amount of work done on the wagon?
75 n*m
27 n*m
120 n*m
45 n*m

Explanation:

Step1: Recall the work formula

Work \(W = F\times d\), where \(F\) is the force and \(d\) is the displacement.

Step2: Substitute the values

Given \(F = 9\space N\) and \(d = 5\space m\). Then \(W=9\times5\).

Step3: Calculate the work

\(W = 45\space N\cdot m\)

Answer:

\(45\space N\cdot m\) (the fourth option)