QUESTION IMAGE
Question
toms journey is shown on the distance-time graph below.
he travelled the final 3 hours of his journey at a constant speed of \\(80\text{ km/h}\\).
work out the value of \\(d\\).
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<reasoning>
Identify the given values from the graph
From the distance-time graph, we can identify the key coordinates and intervals:
- At \(t = 0\), the distance is \(0\text{ km}\).
- At \(t = 2\text{ hours}\), the distance is \(180\text{ km}\).
- From \(t = 2\text{ hours}\) to \(t = 3\text{ hours}\), the distance remains constant at \(180\text{ km}\) (Tom is stationary).
- The final part of the journey starts at \(t = 3\text{ hours}\) and ends at \(t = 6\text{ hours}\).
- The total duration of this final section is:
\[
\Delta t = 6 - 3 = 3\text{ hours}
\]
- The distance at the start of this final section (\(t = 3\)) is \(180\text{ km}\).
- The distance at the end of this final section (\(t = 6\)) is \(d\text{ km}\).
Apply the constant speed formula
We are given that Tom travelled the final 3 hours of his journey at a constant speed of \(80\text{ km/h}\).
The formula relating speed, distance, and time is:
\[
\text{Speed} = \frac{\Delta \text{Distance}}{\Delta \text{Time}}
\]
Substituting the known values into the formula:
\[
80 = \frac{d - 180}{3}
\]
Solve for the unknown value d
Multiply both sides of the equation by 3 to isolate the distance term:
\[
80 \times 3 = d - 180
\]
\[
240 = d - 180
\]
Add 180 to both sides to find \(d\):
\[
d = 240 + 180
\]
\[
d = 420
\]
</reasoning>
<answer>
Work out the value of d.
\(d =\) <blank>420</blank>
</answer>
<post_analysis>
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"Mathematics",
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]
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</post_analysis>
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<reasoning>
Identify the given values from the graph
From the distance-time graph, we can identify the key coordinates and intervals:
- At \(t = 0\), the distance is \(0\text{ km}\).
- At \(t = 2\text{ hours}\), the distance is \(180\text{ km}\).
- From \(t = 2\text{ hours}\) to \(t = 3\text{ hours}\), the distance remains constant at \(180\text{ km}\) (Tom is stationary).
- The final part of the journey starts at \(t = 3\text{ hours}\) and ends at \(t = 6\text{ hours}\).
- The total duration of this final section is:
\[
\Delta t = 6 - 3 = 3\text{ hours}
\]
- The distance at the start of this final section (\(t = 3\)) is \(180\text{ km}\).
- The distance at the end of this final section (\(t = 6\)) is \(d\text{ km}\).
Apply the constant speed formula
We are given that Tom travelled the final 3 hours of his journey at a constant speed of \(80\text{ km/h}\).
The formula relating speed, distance, and time is:
\[
\text{Speed} = \frac{\Delta \text{Distance}}{\Delta \text{Time}}
\]
Substituting the known values into the formula:
\[
80 = \frac{d - 180}{3}
\]
Solve for the unknown value d
Multiply both sides of the equation by 3 to isolate the distance term:
\[
80 \times 3 = d - 180
\]
\[
240 = d - 180
\]
Add 180 to both sides to find \(d\):
\[
d = 240 + 180
\]
\[
d = 420
\]
</reasoning>
<answer>
Work out the value of d.
\(d =\) <blank>420</blank>
</answer>
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