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Question
- think about the inequality x + 2 > -1. circle the values of x makes this true?
Step1: Solve the inequality
$$\begin{align*}
x + 2&>-1\\
x&>-1 - 2\\
x&>-3
\end{align*}$$
Step2: Check the values in the table
In the table, for \(x=-2\), \(x + 2=-2+2 = 0>-1\); for \(x =-\frac{1}{2}\), \(x + 2=-\frac{1}{2}+2=\frac{3}{2}>-1\); for \(x = 1\), \(x + 2=1 + 2=3>-1\); for \(x = 3\), \(x + 2=3+2 = 5>-1\); for \(x = 4\), \(x + 2=4+2=6>-1\); for \(x = 5\), \(x + 2=5+2 = 7>-1\).
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Circle the values \(x=-2\), \(x =-\frac{1}{2}\), \(x = 1\), \(x = 3\), \(x = 4\), \(x = 5\)