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problem reference 10.1
a 0.450 kg block is attached to an unstrained horizontal spring with spring constant 74.0 n/m. the block is given a displacement of 0.0800 m and then released from rest.
what is the magnitude of the force that the spring exerts on the block just before it is released?
33.3 n
5.92 n
2.66 n
463 n

Explanation:

Step1: Recall Hooke's Law

Force from spring: $F = kx$

Step2: Substitute values

$k=74.0\ \text{N/m}$, $x=0.0800\ \text{m}$
$F = 74.0 \times 0.0800 = 5.92\ \text{N}$

Answer:

B. 5.92 N