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question 11 of 22
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question 11
problem reference 6.1
a boy pulls a 10.0 kg sled at a constant velocity for a distance of 18.0 m. he pulls in a direction 38.0° above the horizontal. a 24.0 n frictional force opposes the motion of the sled.
what is the work done by the frictional force?
-545 j
-432 j
-340 j
-280 j

Explanation:

Step1: Recall the work - formula

The formula for work is \(W = Fd\cos\theta\), where \(F\) is the force, \(d\) is the displacement, and \(\theta\) is the angle between the force and the displacement.

Step2: Identify the values

The frictional force \(F_f=- 24.0\space N\) (negative because it opposes the motion), the displacement \(d = 18.0\space m\), and the angle \(\theta=180^{\circ}\) (since the frictional force is opposite to the direction of motion).

Step3: Calculate the work

Substitute the values into the formula: \(W = F_f\times d\times\cos\theta\).

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Answer:

-432 J