Question

tariq and bailey explain how they plot point m at (8, 2)
tariqs explanation:
i start at the origin and move 8 units to the right. then i move 2 units up and plot the point.
baileys explanation:
i locate 8 on the x - axis and 2 on the y - axis. then i plot the point where the grid lines for those coordinates meet.
who is correct?
tariq
bailey
both tariq and bailey

Explanation:

Step1: Analyze Tariq's method

In a coordinate system, starting at the origin \((0,0)\), moving \(8\) units right (along the \(x -\)axis) gives the \(x -\)coordinate \(x = 8\), then moving \(2\) units up (along the \(y -\)axis) gives the \(y -\)coordinate \(y=2\). So the point is \((8,2)\).

Step2: Analyze Bailey's method

Locating \(8\) on the \(x -\)axis (horizontal axis) and \(2\) on the \(y -\)axis (vertical axis), and then finding the intersection of the grid - lines (which is equivalent to moving from the \(x -\)value and \(y -\)value to their common point) also gives the point \((8,2)\) in the coordinate plane.

Since both methods result in plotting the point \((8,2)\), both Tariq and Bailey are correct.

Answer:

Both Tariq and Bailey