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Question
if tanθ = \frac{8}{15}, what is sinθ? sinθ = \frac{?}{}
Step1: Find the hypotenuse
According to the Pythagorean theorem \(c=\sqrt{a^{2}+b^{2}}\), where \(a = 8\), \(b=15\).
\(c=\sqrt{8^{2}+15^{2}}=\sqrt{64 + 225}=\sqrt{289}=17\)
Step2: Calculate \(\sin\theta\)
\(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\), the opposite side is \(8\), hypotenuse is \(17\).
\(\sin\theta=\frac{8}{17}\)
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\(\frac{8}{17}\)