Question

take one bulb out of the circuit and reconnect the wires to get current flowing again. what happens to the brightness of the other bulbs when you take one out?
o the other bulbs get a little dimmer
o the other bulbs stayed the same brightness
o the other bulbs get a little brighter
the next four questions will be about parallel circuits.
without taking apart the series circuit, assemble the parallel circuit shown in the diagram below before moving on.

Explanation:

To solve this, we analyze parallel circuits:

Step 1: Recall Parallel Circuit Properties

In a parallel circuit, each component (like a bulb) has its own independent path for current. The voltage across each branch is equal to the source voltage.

Step 2: Analyze the Effect of One Bulb Failing

If one bulb (branch) fails (e.g., its filament breaks, opening the circuit), the other branches still have a complete path for current. Since voltage across each remaining bulb remains equal to the source voltage (and resistance of each bulb is constant), by \( P = \frac{V^2}{R} \) (power, related to brightness), the power (and thus brightness) of the other bulbs does not change—they still receive the same voltage and draw current based on their own resistance.

Assuming the options are (from typical parallel circuit questions):

• "The other bulbs get a little dimmer" (Incorrect, series behavior)
• "The other bulbs stopped the same brightness" (Correct, parallel independence)
• "The other bulbs get a more brighter" (Incorrect, no voltage increase)

Answer:

The option stating "The other bulbs stayed the same brightness" (exact wording depends on original options, but the correct principle is that parallel branches operate independently, so other bulbs’ brightness doesn’t change when one fails).