Question

the table lists the traits for fruit color where allele r exhibits incomplete dominance over allele r.

heterozygous fruit have orange phenotypes. what percent of offspring are expected to have an orange phenotype if the parent plants are orange (rr) and yellow (rr)?
a 25%
b 50%
c 75%
d 100%

Explanation:

Step1: Determine the gametes

The orange parent \(RR'\) can produce gametes \(R\) and \(R'\). The yellow parent \(R'R'\) can only produce gametes \(R'\).

Step2: Create a Punnett square

	\(R'\)	\(R'\)
\(R'\)	\(R'R'\)	\(R'R'\)

The genotypes of the offspring are \(RR'\) and \(R'R'\) in a 1:1 ratio.

Step3: Calculate the percentage of orange - phenotype offspring

Since \(RR'\) has an orange phenotype, and there are 2 out of 4 (or simplified 1 out of 2) of the offspring with the \(RR'\) genotype. The percentage is \(\frac{1}{2}\times100\% = 50\%\)

Answer:

B. 50%