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suppose \\( \\triangle ith \\cong \\triangle apg \\). which congruency …

Question

suppose \\( \triangle ith \cong \triangle apg \\).
which congruency statement is true?
\\( \overline { i t } \cong \overline { a g } \\)
\\( \overline { t h } \cong \overline { a g } \\)
\\( \overline { i h } \cong \overline { a g } \\)
\\( \overline { t h } \cong \overline { a p } \\)

Explanation:

Step1: Recall congruent triangle properties

When \(\triangle ITH\cong\triangle APG\), corresponding parts are congruent. That is, \(I\) corresponds to \(A\), \(T\) corresponds to \(P\), and \(H\) corresponds to \(G\).

Step2: Analyze each option

  • For \(\overline{IT}\cong\overline{AG}\): \(IT\) corresponds to \(AP\) (not \(AG\)), so this is false.
  • For \(\overline{TH}\cong\overline{AG}\): \(TH\) corresponds to \(PG\) (not \(AG\)), so this is false.
  • For \(\overline{IH}\cong\overline{AG}\): Since \(I\) corresponds to \(A\) and \(H\) corresponds to \(G\), by the property of congruent triangles, \(\overline{IH}\) (side between \(I\) and \(H\)) corresponds to \(\overline{AG}\) (side between \(A\) and \(G\)).
  • For \(\overline{TH}\cong\overline{AP}\): \(TH\) corresponds to \(PG\) (not \(AP\)), so this is false.

Answer:

\(\overline{IH}\cong\overline{AG}\) (the option \(\overline{IH}\cong\overline{AG}\) is true)