Question

suppose 15 quarts of a solution that is 35% antifreeze is mixed with 5 quarts of a solution that is 72% antifreeze. answer the questions below. do not do any rounding. (a) how many quarts of antifreeze are in the resulting mixture? quarts (b) what percentage of the resulting mixture is antifreeze? %

Explanation:

Step1: Calculate total volume of mixture

The first solution has 15 quarts and the second has 5 quarts. So the total volume of the mixture is $15 + 5=20$ quarts.

Step2: Calculate amount of antifreeze in each solution

For the first solution which is 35% antifreeze, the amount of antifreeze is $0.35\times15 = 5.25$ quarts. For the second solution which is 72% antifreeze, the amount of antifreeze is $0.72\times5=3.6$ quarts.

Step3: Calculate total amount of antifreeze in the mixture

The total amount of antifreeze in the mixture is $5.25 + 3.6=8.85$ quarts.

Step4: Answer part (a)

The total amount of antifreeze in the resulting mixture is 8.85 quarts.

Step5: Answer part (b)

To find the percentage of antifreeze in the mixture, use the formula $\text{Percentage}=\frac{\text{Amount of antifreeze}}{\text{Total volume of mixture}}\times100$. Substitute the values: $\frac{8.85}{20}\times 100 = 44.25\%$

Answer:

(a) 8.85 quarts
(b) 44.25%