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the sum of the three numbers is 35. the second number is 25 more than t…

Question

the sum of the three numbers is 35. the second number is 25 more than the first and the third number is double the second. what are the numbers? 1st number=25, 2nd number=50, 3rd number=100 1st number= - 6, 2nd number=19, 3rd number=38 1st number=17, 2nd number=0, 3rd number=18 1st number= - 10, 2nd number=15, 3rd number=30

Explanation:

Step1: Define variables

Let the first number be \( x \). Then the second number is \( x + 25 \), and the third number is \( 2(x + 25) \).

Step2: Set up equation

The sum of the three numbers is 35, so \( x+(x + 25)+2(x + 25)=35 \).

Step3: Simplify equation

Expand and combine like terms: \( x+x + 25+2x+50 = 35 \), which becomes \( 4x+75 = 35 \).

Step4: Solve for \( x \)

Subtract 75 from both sides: \( 4x=35 - 75=-40 \). Then divide by 4: \( x=\frac{-40}{4}=-10 \).

Step5: Find other numbers

Second number: \( -10 + 25 = 15 \). Third number: \( 2\times15 = 30 \).

Answer:

1st number = - 10, 2nd number = 15, 3rd number = 30