Question

subtract the whole numbers.

$2 - 1\frac{1}{4}$
$= 2 - 1 - \frac{1}{4}$
$= \square - \frac{1}{4}$

Explanation:

To solve the problem of subtracting a fraction from a whole number, we first express the whole number as a fraction with the same denominator as the fraction we are subtracting.

Step 1: Rewrite the whole number as a fraction

The whole number here is \( 2 \). To subtract \( \frac{1}{4} \) from \( 2 \), we first rewrite \( 2 \) as a fraction with a denominator of \( 1 \), and then get a common denominator (which is \( 4 \) in this case).

We know that \( 2 = \frac{2}{1} \). To get a denominator of \( 4 \), we multiply the numerator and denominator by \( 4 \):

$$ 2 = \frac{2 \times 4}{1 \times 4} = \frac{8}{4} $$

However, in the given problem, we are looking at \( 2 - 1 - \frac{1}{4} \), but let's focus on the step \( 2 - 1 - \frac{1}{4} \) and the boxed term. First, simplify \( 2 - 1 \):

\( 2 - 1 = 1 \), and we can rewrite \( 1 \) as a fraction with denominator \( 4 \):

$$ 1 = \frac{4}{4} $$

Step 2: Identify the missing term

Looking at the equation \( 2 - 1 - \frac{1}{4} = \square - \frac{1}{4} \), we simplify \( 2 - 1 \) first. Since \( 2 - 1 = 1 \), we can rewrite \( 1 \) as \( \frac{4}{4} \), but more simply, \( 2 - 1 = 1 \), so the boxed term is \( 1 \) (or \( \frac{4}{4} \), but in the context of the problem, \( 1 \) is the simplified form).

Thus, the value in the box is \( \boldsymbol{1} \) (or equivalently \( \frac{4}{4} \), but \( 1 \) is the whole number form).

$$ \boxed{1} $$

Answer:

To solve the problem of subtracting a fraction from a whole number, we first express the whole number as a fraction with the same denominator as the fraction we are subtracting.

Step 1: Rewrite the whole number as a fraction

The whole number here is \( 2 \). To subtract \( \frac{1}{4} \) from \( 2 \), we first rewrite \( 2 \) as a fraction with a denominator of \( 1 \), and then get a common denominator (which is \( 4 \) in this case).

We know that \( 2 = \frac{2}{1} \). To get a denominator of \( 4 \), we multiply the numerator and denominator by \( 4 \):

$$ 2 = \frac{2 \times 4}{1 \times 4} = \frac{8}{4} $$

However, in the given problem, we are looking at \( 2 - 1 - \frac{1}{4} \), but let's focus on the step \( 2 - 1 - \frac{1}{4} \) and the boxed term. First, simplify \( 2 - 1 \):

\( 2 - 1 = 1 \), and we can rewrite \( 1 \) as a fraction with denominator \( 4 \):

$$ 1 = \frac{4}{4} $$

Step 2: Identify the missing term

Looking at the equation \( 2 - 1 - \frac{1}{4} = \square - \frac{1}{4} \), we simplify \( 2 - 1 \) first. Since \( 2 - 1 = 1 \), we can rewrite \( 1 \) as \( \frac{4}{4} \), but more simply, \( 2 - 1 = 1 \), so the boxed term is \( 1 \) (or \( \frac{4}{4} \), but in the context of the problem, \( 1 \) is the simplified form).

Thus, the value in the box is \( \boldsymbol{1} \) (or equivalently \( \frac{4}{4} \), but \( 1 \) is the whole number form).

$$ \boxed{1} $$