subtract unlike fractions
directions: find the difference.

$\frac{3}{4} - \frac{5}{8} =$

$\frac{3}{6} - \frac{1}{4} =$

$\frac{5}{7} - \frac{1}{3} =$

$\frac{1}{3} - \frac{1}{6} =$

$\frac{6}{9} - \frac{5}{10} =$

$\frac{2}{3} - \frac{2}{6} =$

$\frac{3}{7} - \frac{4}{11} =$

Question

subtract unlike fractions
directions: find the difference.

$\frac{3}{4} - \frac{5}{8} =$

$\frac{3}{6} - \frac{1}{4} =$

$\frac{5}{7} - \frac{1}{3} =$

$\frac{1}{3} - \frac{1}{6} =$

$\frac{6}{9} - \frac{5}{10} =$

$\frac{2}{3} - \frac{2}{6} =$

$\frac{3}{7} - \frac{4}{11} =$

Accepted Answer

{ "quality": "clear", "question_count": 7, "skills_matched": [ "step_cot", "table_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [], "new_concepts": [ "Fraction Subtraction", "Least Common Denominator" ], "current_concepts": [ "Fraction Subtraction", "Least Common Denominator", "Simplifying Fractions" ] } ## Find common denominators $$ \begin{aligned} \text{1. } & \text{LCD}(4, 8) = 8 \implies \frac{3}{4} - \frac{5}{8} = \frac{6}{8} - \frac{5}{8} \ \text{2. } & \text{LCD}(6, 4) = 12 \implies \frac{3}{6} - \frac{1}{4} = \frac{6}{12} - \frac{3}{12} \ \text{3. } & \text{LCD}(7, 3) = 21 \implies \frac{5}{7} - \frac{1}{3} = \frac{15}{21} - \frac{7}{21} \ \text{4. } & \text{LCD}(3, 6) = 6 \implies \frac{1}{3} - \frac{1}{6} = \frac{2}{6} - \frac{1}{6} \ \text{5. } & \text{LCD}(9, 10) = 90 \implies \frac{6}{9} - \frac{5}{10} = \frac{2}{3} - \frac{1}{2} = \frac{4}{6} - \frac{3}{6} \ \text{6. } & \text{LCD}(3, 6) = 6 \implies \frac{2}{3} - \frac{2}{6} = \frac{4}{6} - \frac{2}{6} \ \text{7. } & \text{LCD}(7, 11) = 77 \implies \frac{3}{7} - \frac{4}{11} = \frac{33}{77} - \frac{28}{77} \end{aligned} $$ ## Subtract the numerators $$ \begin{aligned} \text{1. } & \frac{6-5}{8} = \frac{1}{8} \ \text{2. } & \frac{6-3}{12} = \frac{3}{12} \ \text{3. } & \frac{15-7}{21} = \frac{8}{21} \ \text{4. } & \frac{2-1}{6} = \frac{1}{6} \ \text{5. } & \frac{4-3}{6} = \frac{1}{6} \ \text{6. } & \frac{4-2}{6} = \frac{2}{6} \ \text{7. } & \frac{33-28}{77} = \frac{5}{77} \end{aligned} $$ ## Simplify the fractions $$ \begin{aligned} \text{1. } & \frac{1}{8} \ \text{2. } & \frac{3}{12} = \frac{1}{4} \ \text{3. } & \frac{8}{21} \ \text{4. } & \frac{1}{6} \ \text{5. } & \frac{1}{6} \ \text{6. } & \frac{2}{6} = \frac{1}{3} \ \text{7. } & \frac{5}{77} \end{aligned} $$ | No. | Problem | Answer | |---|---|---| | 1 | $\frac{3}{4} - \frac{5}{8}$ | $\frac{1}{8}$ | | 2 | $\frac{3}{6} - \frac{1}{4}$ | $\frac{1}{4}$ | | 3 | $\frac{5}{7} - \frac{1}{3}$ | $\frac{8}{21}$ | | 4 | $\frac{1}{3} - \frac{1}{6}$ | $\frac{1}{6}$ | | 5 | $\frac{6}{9} - \frac{5}{10}$ | $\frac{1}{6}$ | | 6 | $\frac{2}{3} - \frac{2}{6}$ | $\frac{1}{3}$ | | 7 | $\frac{3}{7} - \frac{4}{11}$ | $\frac{5}{77}$ | { "subject": "Mathematics", "question_type": "Multi-part", "knowledge_point": [ "Mathematics", "Algebra", "Fraction Subtraction" ] }

No.	Problem	Answer
2	\(\frac{3}{6} - \frac{1}{4}\)	\(\frac{1}{4}\)
3	\(\frac{5}{7} - \frac{1}{3}\)	\(\frac{8}{21}\)
4	\(\frac{1}{3} - \frac{1}{6}\)	\(\frac{1}{6}\)
5	\(\frac{6}{9} - \frac{5}{10}\)	\(\frac{1}{6}\)
6	\(\frac{2}{3} - \frac{2}{6}\)	\(\frac{1}{3}\)
7	\(\frac{3}{7} - \frac{4}{11}\)	\(\frac{5}{77}\)

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QUESTION IMAGE

Question

Explanation:

Find common denominators

Subtract the numerators

Simplify the fractions

Answer: