Question

subtract, as shown in the examples.
ex. $\frac{4}{5} - \frac{1}{5} = \frac{3}{5}$
(1) $\frac{4}{5} - \frac{2}{5} =$
(2) $\frac{4}{5} - \frac{3}{5} =$
(3) $\frac{6}{7} - \frac{2}{7} =$
(4) $\frac{4}{7} - \frac{3}{7} =$
(5) $\frac{4}{7} - \frac{4}{7} = 0$
(6) $\frac{8}{9} - \frac{1}{9} =$
(7) $\frac{8}{9} - \frac{4}{9} =$
(8) $\frac{8}{9} - \frac{8}{9} =$

Explanation:

Step1: Solve \(\frac{4}{5} - \frac{2}{5}\)

For subtracting fractions with the same denominator, we subtract the numerators and keep the denominator the same. So, \(4 - 2 = 2\), and the denominator is 5. Thus, \(\frac{4}{5} - \frac{2}{5} = \frac{4 - 2}{5} = \frac{2}{5}\).

Step2: Solve \(\frac{4}{5} - \frac{3}{5}\)

Using the same rule for subtracting fractions with the same denominator, subtract the numerators: \(4 - 3 = 1\), denominator remains 5. So, \(\frac{4}{5} - \frac{3}{5} = \frac{4 - 3}{5} = \frac{1}{5}\).

Step3: Solve \(\frac{6}{7} - \frac{2}{7}\)

Subtract the numerators: \(6 - 2 = 4\), denominator is 7. So, \(\frac{6}{7} - \frac{2}{7} = \frac{6 - 2}{7} = \frac{4}{7}\).

Step4: Solve \(\frac{4}{7} - \frac{3}{7}\)

Subtract the numerators: \(4 - 3 = 1\), denominator is 7. So, \(\frac{4}{7} - \frac{3}{7} = \frac{4 - 3}{7} = \frac{1}{7}\).

Step5: Solve \(\frac{8}{9} - \frac{1}{9}\)

Subtract the numerators: \(8 - 1 = 7\), denominator is 9. So, \(\frac{8}{9} - \frac{1}{9} = \frac{8 - 1}{9} = \frac{7}{9}\).

Step6: Solve \(\frac{8}{9} - \frac{4}{9}\)

Subtract the numerators: \(8 - 4 = 4\), denominator is 9. So, \(\frac{8}{9} - \frac{4}{9} = \frac{8 - 4}{9} = \frac{4}{9}\).

Step7: Solve \(\frac{8}{9} - \frac{8}{9}\)

Subtract the numerators: \(8 - 8 = 0\), denominator is 9. So, \(\frac{8}{9} - \frac{8}{9} = \frac{8 - 8}{9} = 0\).

Answer:

(1) \(\frac{2}{5}\)
(2) \(\frac{1}{5}\)
(3) \(\frac{4}{7}\)
(4) \(\frac{1}{7}\)
(6) \(\frac{7}{9}\)
(7) \(\frac{4}{9}\)
(8) \(0\)