Question

subtract.
(7q - 3) - (4q³ + 8q² - 7q - 1)

Explanation:

Step1: Distribute the negative sign

To subtract the polynomial, we distribute the negative sign to each term inside the second parentheses:
\((7q - 3) - (4q^3 + 8q^2 - 7q - 1) = 7q - 3 - 4q^3 - 8q^2 + 7q + 1\)

Step2: Combine like terms

• For the \(q^3\) term: \(-4q^3\) (no other \(q^3\) terms)
• For the \(q^2\) term: \(-8q^2\) (no other \(q^2\) terms)
• For the \(q\) terms: \(7q + 7q = 14q\)
• For the constant terms: \(-3 + 1 = -2\)

Putting it all together: \(-4q^3 - 8q^2 + 14q - 2\)

Answer:

\(-4q^3 - 8q^2 + 14q - 2\)