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Question
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$-4log_4(x)+1 = 13$
answer attempt 1 out of 2
$x =$
Step1: Isolate the logarithmic term
Subtract 1 from both sides of the equation:
$$-4\log_4(x)=13 - 1$$
$$-4\log_4(x)=12$$
Step2: Solve for the logarithmic term
Divide both sides by - 4:
$$\log_4(x)=\frac{12}{-4}=-3$$
Step3: Convert to exponential form
Using the definition of logarithms \(y = \log_a(x)\) is equivalent to \(x=a^y\), we have:
$$x = 4^{-3}$$
$$x=\frac{1}{4^3}=\frac{1}{64}$$
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\(\frac{1}{64}\)