Question

1. a student performs an experiment with 3 unknown fluids and obtains the following measurements. fluid a: m = 2060 g ; v = 2000 ml fluid b: m = 672 g ; v = 850 ml fluid c: m = 990 g ; v = 1100 ml draw how the fluids would be layered if they were combined in a beaker.

Explanation:

Step1: Calculate density of Fluid A

Density formula: $
ho = \frac{m}{V}$. For Fluid A, $m = 2060\ \text{g}$, $V = 2000\ \text{mL}$. So $
ho_A = \frac{2060}{2000} = 1.03\ \text{g/mL}$.

Step2: Calculate density of Fluid B

For Fluid B, $m = 672\ \text{g}$, $V = 850\ \text{mL}$. $
ho_B = \frac{672}{850} \approx 0.79\ \text{g/mL}$.

Step3: Calculate density of Fluid C

For Fluid C, $m = 990\ \text{g}$, $V = 1100\ \text{mL}$. $
ho_C = \frac{990}{1100} = 0.9\ \text{g/mL}$.

Step4: Compare densities

Densities: $
ho_B \approx 0.79\ \text{g/mL}$, $
ho_C = 0.9\ \text{g/mL}$, $
ho_A = 1.03\ \text{g/mL}$. So order from least to most dense: Fluid B, Fluid C, Fluid A.

Answer:

When combined, the fluid with the lowest density (Fluid B) will be on top, then Fluid C (middle), and Fluid A (bottom) since density determines layering (less dense fluids float on more dense ones). The layering from top to bottom is: Fluid B, Fluid C, Fluid A.