QUESTION IMAGE
Question
structure of dna: chargaffs rules
chargaff discovered that the total number of purines (adenine and guanine) is always
equal to the total number of pyrimidines (thymine and cytosine).
lets understand why - answer these questions to unpack chargaffs rule:
- which base does adenine pair with?
- how many adenines are there on strand a?
there are 2 adenines
- how many thymines are there on strand b?
there are 2 thymines
- the number of cytosines on strand a is equal
to the number of what on strand b?
- count the number of purines (a and g) and the number
of pyrimidines (t and c) and then write these as a ratio.
2 guanine
Step1: Identify base - pairing rules
In DNA, adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G).
Step2: Answer question 1
Since adenine (A) pairs with thymine (T), but looking at the base - pairing in the given DNA strands (in DNA double - strand, A pairs with T in complementary strand. But if we consider the question about which base adenine pairs with in terms of Chargaff's rules (more about quantity in double - strand, but in base - pairing, A pairs with T). However, if we assume it's about complementary base in double - strand, from the strand A (with bases A, C, A, C, T) and strand B (T, G, T, G, A), adenine (A) pairs with thymine (T).
Step3: Answer question 2
Count adenines in strand A. In strand A (sequence: A, C, A, C, T), the number of adenines is 2.
Step4: Answer question 3
Since A pairs with T in double - strand DNA. The number of thymines in strand B is equal to the number of adenines in strand A. Since there are 2 adenines in strand A, there are 2 thymines in strand B.
Step5: Answer question 4
Count cytosines in strand A (sequence: A, C, A, C, T). The number of cytosines in strand A is 2. Since C pairs with G, the number of guanines on strand B is 2.
Step6: Answer question 5
Count purines (A and G) and pyrimidines (T and C).
- Purines: Adenine (A) count in strand A is 2, guanine (G) count in strand B (paired with C in strand A) is 2. Total purines \(=2 + 2=4\)
- Pyrimidines: Thymine (T) count in strand B (paired with A in strand A) is 2, cytosine (C) count in strand A is 2. Total pyrimidines \(=2+2 = 4\)
- Ratio of purines to pyrimidines \(\frac{4}{4}=1\)
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- Thymine (T)
- 2
- 2
- 2
- The ratio of purines (A + G) to pyrimidines (T + C) is \(1\) (since \( (2 + 2)\div(2 + 2)=1\))