Question

spooner and wendy both have a hand with heterozygous genotypes (hh).
spooner
wendy
phenotype probability (%)
hand:
no hand:

Explanation:

Step1: Count total genotypes

The Punnett square has 4 cells: \(HH\), \(Hh\), \(Hh\), \(hh\). So total number of possible genotypes is \(4\).

Step2: Count "Hand" genotypes

Genotypes with "Hand" (assuming \(H\) is dominant for hand, so \(HH\), \(Hh\), \(Hh\)): there are \(3\) such genotypes. Probability for "Hand" is \(\frac{3}{4} \times 100\% = 75\%\).

Step3: Count "No hand" genotypes

Genotype with "No hand" ( \(hh\)): there is \(1\) such genotype. Probability for "No hand" is \(\frac{1}{4} \times 100\% = 25\%\).

Answer:

Hand: \(75\%\)
No hand: \(25\%\)