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4. spongebob squarepants recently met spongesusie roundpants at a dance…

Question

  1. spongebob squarepants recently met spongesusie roundpants at a dance. spongebob is homozygous recessive for his square shape, but spongesusie is heterozygous for her round shape. create a punnett square to show the possibilities that would result if spongebob and spongesusie had children. hint: read question #2! a. list the possible genotypes and phenotypes for their children. g: ____________ p: __________ b. what are the chances of a child with a square shape? __ out of __ or __ % c. what are the chances of a child with a round shape? __ out of __ or ____ %

Explanation:

Step1: Define alleles

Let's assume that the allele for round shape (R) is dominant and the allele for square shape (r) is recessive. Sponge - Bob is homozygous recessive (rr) and Sponge - Susie is heterozygous (Rr).

Step2: Set up Punnett square

The possible gametes from Sponge - Bob are all r. The possible gametes from Sponge - Susie are R and r. We set up a 2x2 Punnett square. The top of the square has the gametes from Sponge - Susie (R and r) and the side has the gametes from Sponge - Bob (r and r).

Step3: Fill in Punnett square

When we fill in the Punnett square:

Rr
rRrrr

Step4: Determine genotypes and phenotypes

The genotypes are Rr and rr. The phenotype for Rr is round - shaped and for rr is square - shaped.

Step5: Calculate probabilities

There are 2 Rr and 2 rr out of 4 total offspring.
For a square - shaped child (rr), the probability is 2 out of 4 or 50%.
For a round - shaped child (Rr), the probability is 2 out of 4 or 50%.

Answer:

A. Genotypes: Rr, rr; Phenotypes: Round - shaped, Square - shaped
B. 2 out of 4 or 50%
C. 2 out of 4 or 50%