Question

3.) the specific heat of copper is 0.39 j/g °c. how much heat is needed to raise the temperature of 1250g of copper from 25°c to 55°c?

Explanation:

Step1: Identify the formula

The formula for heat \(Q = mc\Delta T\), where \(m\) is mass, \(c\) is specific heat, \(\Delta T=T_{final}-T_{initial}\)

Step2: Substitute the values

Given \(m = 1250g\), \(c=0.39J/g^{\circ}C\), \(\Delta T=55 - 25=30^{\circ}C\)
\(Q=(1250g)\times(0.39J/g^{\circ}C)\times(30^{\circ}C)\)

Step3: Calculate the value

\(Q = 1250\times0.39\times30\)
\(Q=1250\times11.7\)
\(Q = 14625J\)

Answer:

\(14625J\)