Question

special relativity: crash course physics #...
special relativity: crash course physics #42
multiple - choice question
if you travel at the speed of light, what does the denominator of this equation equal? hint:
in this equation, the denominator includes everything inside of the square root
1
100
0

Explanation:

Step1: Sustituir \(v = c\) en la expresión del denominador

El denominador es \(\sqrt{1-\frac{v^{2}}{c^{2}}}\). Si \(v = c\), entonces \(\frac{v^{2}}{c^{2}}=\frac{c^{2}}{c^{2}} = 1\).

Step2: Calcular el valor del denominador

Sustituyendo \(\frac{v^{2}}{c^{2}} = 1\) en \(\sqrt{1-\frac{v^{2}}{c^{2}}}\), obtenemos \(\sqrt{1 - 1}=\sqrt{0}=0\).

Answer:

0