Question

1. a space probe is launched into space from earth’s surface. which graph represents the relationship between the magnitude of the gravitational force exerted on earth by the space probe and the distance between the space probe and the center of earth? (four graphs labeled (1), (2), (3), (4) with force on y - axis and distance on x - axis: (1) horizontal line, (2) curve decreasing rapidly then slowly, (3) straight line decreasing to zero, (4) curve increasing)
2. the diagram shows two bowling balls, a and b, each having a mass of 7 kilograms, placed 2 meters apart. (diagram with ball a (7.00 kg) and ball b (7.00 kg) 2.00 m apart) what is the magnitude of the gravitational force exerted by ball a on ball b?
3. $8.17 \times 10^{-9}$ n
4. $1.63 \times 10^{-8}$ n
5. $8.17 \times 10^{-10}$ n
6. $1.17 \times 10^{-10}$ n
7. a 60 - kg physics student would weigh 1560 n on the surface of planet x. what is the magnitude of the...
8. a container of rocks with a mass of 65 kilograms is brought back from the moon’s surface where the acceleration due to gravity is 1.62 meters per second². what is the weight of the container of rocks on earth’s surface?
9. 638 n
10. 394 n
11. 105 n
12. 65 n
13. the graph below represents the relationship between gravitational force and mass for objects near the surface of earth. (graph with... )

Explanation:

Step1: Identify gravity formula

Gravitational force: $F = G\frac{m_1m_2}{r^2}$ (inverse square law).

Step2: Analyze graph shape

Force decreases as $1/r^2$ with distance. Graph (2) matches this curve.

Step1: List known values

$m_A = m_B = 7.00\ \text{kg}$, $r = 2.00\ \text{m}$, $G = 6.67×10^{-11}\ \text{N·m}^2/\text{kg}^2$.

Step2: Apply gravity formula

$F = (6.67×10^{-11})×\frac{7×7}{2^2} = 6.67×10^{-11}×\frac{49}{4} ≈ 8.17×10^{-10}\ \text{N}$.

Step1: Identify weight formula

Weight on Earth: $W = m×g$, $g = 9.8\ \text{m/s}^2$, $m = 65\ \text{kg}$.

Step2: Calculate weight

$W = 65×9.8 = 637\ \text{N} ≈ 638\ \text{N}$.

Answer:

The graph labeled (2)