Question

solve for j.

$39j^2 - 19j = 0$

write each solution as an integer, proper fraction, or improper fraction in simplest form. if there are multiple solutions, separate them with commas.

$j = \square$

Explanation:

Step1: Factor out common term $j$

$j(39j - 19) = 0$

Step2: Set each factor to 0

$j = 0 \quad \text{or} \quad 39j - 19 = 0$

Step3: Solve linear equation

$39j = 19 \implies j = \frac{19}{39}$

Answer:

$0, \frac{19}{39}$