Question

solve for the value of y. solve on paper, or show your work below. then enter your answer on zearn. (4)
4y + 11 ≤ 31
4y + 11 = 31
y = \boxed{}

Explanation:

Step1: Subtract 11 from both sides

To isolate the term with \( y \), we subtract 11 from both sides of the inequality \( 4y + 11 \leq 31 \). This gives us \( 4y + 11 - 11 \leq 31 - 11 \), which simplifies to \( 4y \leq 20 \).

Step2: Divide both sides by 4

To solve for \( y \), we divide both sides of the inequality \( 4y \leq 20 \) by 4. This gives us \( \frac{4y}{4} \leq \frac{20}{4} \), which simplifies to \( y \leq 5 \). For the equation \( 4y + 11 = 31 \) (to find the boundary value), following the same steps: subtract 11, \( 4y = 31 - 11 = 20 \), then divide by 4, \( y = \frac{20}{4} = 5 \).

Answer:

\( y \leq 5 \) (for the inequality) and for the equation \( y = 5 \)