Question

solve using elimination.
$x + 3y = -1$
$x + 8y = 14$
$\left(\square, \square\
ight)$

Explanation:

Step1: Subtract the two equations

To eliminate \( x \), subtract the first equation \( x + 3y = -1 \) from the second equation \( x + 8y = 14 \).

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Step2: Solve for \( y \)

Divide both sides of the equation \( 5y = 15 \) by 5.

$$ y = \frac{15}{5} = 3 $$

Step3: Substitute \( y = 3 \) into one of the original equations

Substitute \( y = 3 \) into the first equation \( x + 3y = -1 \).

$$ x + 3(3) = -1\\ x + 9 = -1 $$

Step4: Solve for \( x \)

Subtract 9 from both sides of the equation \( x + 9 = -1 \).

$$ x = -1 - 9 = -10 $$

Answer:

\((-10, 3)\)