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Question
solve the system by substitution.
y = 8x + 32
y = -8x
Step1: Substitute \( y = -8x \) into \( y = 8x + 32 \)
Since both equations equal \( y \), we can set them equal to each other: \( -8x = 8x + 32 \)
Step2: Solve for \( x \)
Add \( 8x \) to both sides: \( 0 = 16x + 32 \)
Subtract 32 from both sides: \( -32 = 16x \)
Divide by 16: \( x = -2 \)
Step3: Substitute \( x = -2 \) into \( y = -8x \)
\( y = -8(-2) = 16 \)
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The solution to the system is \( x = -2 \) and \( y = 16 \), or the ordered pair \( (-2, 16) \)