QUESTION IMAGE
Question
solve the system by substitution.
y = -2x + 30
y = 4x
Step1: Substitute \( y = 4x \) into \( y=-2x + 30 \)
Since both equations are solved for \( y \), we can substitute the expression for \( y \) from the second equation into the first. So we get \( 4x=-2x + 30 \).
Step2: Solve for \( x \)
Add \( 2x \) to both sides of the equation \( 4x=-2x + 30 \) to get \( 4x + 2x=-2x+2x + 30 \), which simplifies to \( 6x = 30 \). Then divide both sides by 6: \( x=\frac{30}{6}=5 \).
Step3: Substitute \( x = 5 \) into \( y = 4x \)
Now that we have \( x = 5 \), we substitute it into the equation \( y = 4x \). So \( y=4\times5 = 20 \).
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The solution to the system is \( x = 5 \) and \( y = 20 \), or as an ordered pair \( (5,20) \).