Question

1. solve the system of equations.

3x - 2y = -2
-x + 3y = 3
options: (0, -1), (0, 1), (1, 0), (-1, 0)

Explanation:

Step1: Solve the second equation for x

From \(-x + 3y = 3\), we can rewrite it as \(x = 3y - 3\).

Step2: Substitute x into the first equation

Substitute \(x = 3y - 3\) into \(3x - 2y = -2\):

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Step3: Find x using y = 1

Substitute \(y = 1\) into \(x = 3y - 3\):
\(x = 3(1) - 3 = 0\)
So the solution is \((0, 1)\).

Answer:

B. (0,1) (assuming the second option is labeled as B, if the first option is A, adjust accordingly. Since the options are (0,-1), (0,1), (1,0), (-1,0), the correct one is (0,1))